Difference in time of both the clocks after 1 minute will be the sum of gain in time of one clock and delay in time of the second clock in 1 minute.
First clock will be 30 minutes ahead of the second clock in 20 hours.
   It's given in the question,
- Both the clocks are set at 6 A.M.
- First clock gains 30 seconds every hour
Since, 1 second = [tex]\frac{1}{60}[/tex] minutes
Therefore, 30 seconds = [tex]\frac{30}{60}[/tex] minutes
                   = 0.5 minutes
That means first clocks gains 0.5 minutes in every hour.
- Second clock loses 1 minute every hour
Therefore, difference in both the clocks in every hour = 1 + 0.5
                                              = 1.5 minutes
Difference of 30 minutes will be in the duration = [tex]\frac{30}{1.5}[/tex] hours
                                        = 20 hours
       First clock will be 30 minutes ahead of the second clock in 20 hours.
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