00francescaedwards
00francescaedwards 00francescaedwards
  • 03-10-2021
  • Mathematics
contestada

10-root18/root2 = a+broot2

10root18root2 abroot2 class=

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Аноним Аноним
  • 03-10-2021

Step-by-step explanation:

[tex] \frac{10 - \sqrt{18} }{ \sqrt{2} } = a + b \sqrt{2} [/tex]

[tex] \frac{10}{ \sqrt{2} } + \frac{ - \sqrt{18} }{ \sqrt{2} } [/tex]

[tex] 5 \sqrt{2} + ( \frac{ - \sqrt{18} }{ \sqrt{2} } ) \times \sqrt{2} [/tex]

[tex]a = 5 \sqrt{2} [/tex]

[tex]b = \frac{ - \sqrt{18} }{ \sqrt{2} } [/tex]

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